Latest update
1.更新語音識別SDK
英語脫口說 (Talk to Lucy) APK Description
英語脫口說是一款透過 AI 技術打造的英語口說訓練課程，創造不斷刺栀與回應的口說環境，協助您自然、直覺的開口說英語。
課程全程以「對話互動」進行，輔以音效、圖像、動畫、即時評分，提供有效的語言刺栀。
單元的學砒流程是：
(1) 聆聽對話 (Listen) →
(2) 語音跟讀 (Repeat) →
(3) 句型練砒 (Drills) →
(4) 實境對話 (Conversation)
對話進行當中，系統自動記錄你的學砒歷程，包含四個面向：流暢度、完成度、語法、發音，讓您清楚看到努力的成果。
內容編排由淺至深，即你基礎差也能輕鬆學，包含兒童會話、成人會話、GEPT口說模擬、句型訓練等四種課程。每週持續新增內容喔！
How to install 英語脫口說 (Talk to Lucy) APK bundles for Android
Once you have downloaded an Android App Bundle, you can install it using a dedicated app bundle installer app. You can install .apks, .xapk, split apk files, and unencrypted .apkm files using the Split APKs Installer (SAI). SAI is considered the gold standard for installing app bundles in the Android community. Here’s how to use the SAI app to install split apks. Download 英語脫口說 (Talk to Lucy) APK file (com.kteoc.lucybot_43_13373295.apk) from APKBundles.com, then follow these steps:
Update Phone Settings
- Go to your phone Settings page
- Tap Security or Applications (varies with device)
- Check the Unknown Sources box
- Confirm with OK
Go to Downloads
- Open Downloads on your device by going to My Files or Files
- Tap the APK file you downloaded (com.kteoc.lucybot_43_13373295.apk)
- Tap Install when prompted, the APK file you downloaded will be installed on your device.
How to install 英語脫口說 (Talk to Lucy) APK, Split APK (APK Bundles) on Windows PC 7/8/10/11 or MAC?
Download 英語脫口說 (Talk to Lucy) APK file (com.kteoc.lucybot_43_13373295.apk) from APKBundles.com to your PC (ex: C://temp/(com.kteoc.lucybot_43_13373295.apk), then follow these steps appear on screen.
Using Emulator:
- Download And Install one Emulator Softwares (Ex: Bluestacks, GenyMotion, NoxPlayer)
- Simple install APK on PC by drag and drop file com.kteoc.lucybot_43_13373295.apk on Emulator screen
英語脫口說 (Talk to Lucy) APK Pros & Cons
Pros
- This app is safe, it's not require high risk permissions
- Compatible with 64-bit device (some android device and current Bluestacks)
Cons
- No best performance On PC (Windows, MAC) (because it's not exists X86 variant)
